选择 (13 10:41:10)若y=mxm2+m+1是正比例函数关系式,则m等于:A.0 B.1 C.0或
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选择 (13 10:41:10)若y=mxm2+m+1是正比例函数关系式,则m等于:A.0 B.1 C.0或
选择 (13 10:41:10)
若y=mxm2+m+1是正比例函数关系式,则m等于:
A.0 B.1 C.0或1 D.±1
选择 (13 10:41:10)若y=mxm2+m+1是正比例函数关系式,则m等于:A.0 B.1 C.0或
没有正确答案,
应该是 m=-1
恩,正确答案是-1,既然是成正比关系,那么M+1就要等于0了
既然是成正比关系 那么后面的m+1要=0 所以m=-1 你这上面没正确答案啊............