求不定积分∫2x*ln(x+2)

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求不定积分∫2x*ln(x+2)
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求不定积分∫2x*ln(x+2)
求不定积分∫2x*ln(x+2)

求不定积分∫2x*ln(x+2)
原式=∫ln(x+2)dx²
=x²ln(x+2)-∫x²dln(x+2)
=x²ln(x+2)-∫(x²-4+4)/(x+2) dx
=x²ln(x+2)-∫[x+2+4/(x+2)] dx
=x²ln(x+2)-x²/2-2x-4ln|x+2|+C

分部积分嘛,将2x与dx结合为d(x^2),则原式=x^2* ln(x+2)-∫x^2d(ln(x+2)),而d(ln(x+2))=dx/(x+2),后面你会吧