求sin(-1320)cos1110+cos(-1020)sin750的值

求sin(-1320)cos1110+cos(-1020)sin750的值 sin(-1320°)cos1110°的值 sin(-1380`)cos1110`+ cos(-1020`)sin750`+tan495`求过程 sin(-1320)cos1110+cos(-1020)sin750+tan495的值. sin（-1320°）、cos1110°、cos（-1020°)、sin750°、tan495°等于多少 求值 sin(-1320°)cos1110°+cos(-1020°)sin750°+cos495° sin-1320度cos1110度+cos-1020度sin750度+tan495度=? sin（-1320°）cos1110°+cos（-1020°)sin750°+tan495° sin(-1395)cos1110+cos(-1020)sin750 问一道数学题 sin(－1320)乘以cos1110＋cos(－1020)乘以sin720,最后再加上tan495,等于? 求值：sin(-1350)cos1110+cos(-1020)sin750+tan405 化简:sin780°cos1110°+cos(-660°)sin(-690°)+tan585°cos1440° 计算不太明白...求值sin(-1320°）*cos1110°+cos（-1020°）sin750°+tan（-405°）求值sin25π/6+cos25π/3+tan25π/4+sin7π/3*cos13π/6-cos5π/3 Sin ²A+sin²B+sin²C＜2,求三角形形状 sin^2 A=sin^2 B+sinBsinC+sin^2 C 求A角 在三角形abc中,已知sin²a+sin²b=sin²c+sina+sinb,求角c C语言求三角函数f(x,y,z)=sin(x)/(sin(x-y)*sin(x-z))+sin(y)/(sin(y-x)*sin(y-z))+sin(z)/(sin(z-x)*sin(z-y))代码#include #include double fun(double x,double y,double z){double a,b,c,sum;a=sin(x)/(sin(x-y)*sin(x-z));b=sin(y)/(sin(y-x)*sin(y-z));c 在三角形ABC中,若sin^2A=sin^2B+sin^2C+sinBsinC,求A的值