d (ln(x^2 + y )) 怎么算

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d (ln(x^2 + y )) 怎么算
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d (ln(x^2 + y )) 怎么算
d (ln(x^2 + y )) 怎么算

d (ln(x^2 + y )) 怎么算
d (ln(x^2 + y ))
= [1/(x^2+y)].( 2xdx + dy)

(2x+y')/(x^2 + y)

z=ln(x ²+y)
∂z/∂x= (1/(x²+y))(2x)=2x/(x ²+y)
∂z/∂y= (1/(x²+y))=1/(x ²+y)
d(ln(x ²+y)=(∂z/∂x)dx+(∂z/∂y)dy=(2xdx+dy)/(x ²+y)