在正方形ABCD中,E是直线BC上一点,连接AE,过C作CF垂直于AE与F,连接BF.已知,在正方形ABCD中,点E是直线BC上一点,过C作CF⊥AE于F,连结BF如图1当点E在边BC上时,求证AF-CF=√2BF,
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![在正方形ABCD中,E是直线BC上一点,连接AE,过C作CF垂直于AE与F,连接BF.已知,在正方形ABCD中,点E是直线BC上一点,过C作CF⊥AE于F,连结BF如图1当点E在边BC上时,求证AF-CF=√2BF,](/uploads/image/z/8801304-24-4.jpg?t=%E5%9C%A8%E6%AD%A3%E6%96%B9%E5%BD%A2ABCD%E4%B8%AD%2CE%E6%98%AF%E7%9B%B4%E7%BA%BFBC%E4%B8%8A%E4%B8%80%E7%82%B9%2C%E8%BF%9E%E6%8E%A5AE%2C%E8%BF%87C%E4%BD%9CCF%E5%9E%82%E7%9B%B4%E4%BA%8EAE%E4%B8%8EF%2C%E8%BF%9E%E6%8E%A5BF.%E5%B7%B2%E7%9F%A5%2C%E5%9C%A8%E6%AD%A3%E6%96%B9%E5%BD%A2ABCD%E4%B8%AD%2C%E7%82%B9E%E6%98%AF%E7%9B%B4%E7%BA%BFBC%E4%B8%8A%E4%B8%80%E7%82%B9%2C%E8%BF%87C%E4%BD%9CCF%E2%8A%A5AE%E4%BA%8EF%2C%E8%BF%9E%E7%BB%93BF%E5%A6%82%E5%9B%BE1%E5%BD%93%E7%82%B9E%E5%9C%A8%E8%BE%B9BC%E4%B8%8A%E6%97%B6%2C%E6%B1%82%E8%AF%81AF-CF%3D%E2%88%9A2BF%2C)
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