若(x^2+y^2+2)(x^2+y^2-4)=7,则x^2+y^2的值是_____?
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若(x^2+y^2+2)(x^2+y^2-4)=7,则x^2+y^2的值是_____?
若(x^2+y^2+2)(x^2+y^2-4)=7,则x^2+y^2的值是_____?
若(x^2+y^2+2)(x^2+y^2-4)=7,则x^2+y^2的值是_____?
设x^2+y^2=t
原式改为(t+2)(t-4)=7,即t^2-2t-15=0
所以t=5或-3
因为x^2+y^2>0,所以x^2+y^2=5
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