试用消元法解下列方程组:详细解释下{ X1-x2+x3-x4=0 2x1-x2+3x3-2x4=-1 3x1-2x2-x3+2x4=4

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试用消元法解下列方程组:详细解释下{ X1-x2+x3-x4=0               2x1-x2+3x3-2x4=-1               3x1-2x2-x3+2x4=4
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试用消元法解下列方程组:详细解释下{ X1-x2+x3-x4=0 2x1-x2+3x3-2x4=-1 3x1-2x2-x3+2x4=4
试用消元法解下列方程组:详细解释下
{ X1-x2+x3-x4=0
2x1-x2+3x3-2x4=-1
3x1-2x2-x3+2x4=4

试用消元法解下列方程组:详细解释下{ X1-x2+x3-x4=0 2x1-x2+3x3-2x4=-1 3x1-2x2-x3+2x4=4
我给你做出来了,我是用数学编辑器做的,花了我好长时间,