已知正方形ABCD中,M是BC的中点,MN⊥AM,MN与∠DCE的平分线相交于N,E在BC的延长线上,求证:AM=MN
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![已知正方形ABCD中,M是BC的中点,MN⊥AM,MN与∠DCE的平分线相交于N,E在BC的延长线上,求证:AM=MN](/uploads/image/z/8903615-23-5.jpg?t=%E5%B7%B2%E7%9F%A5%E6%AD%A3%E6%96%B9%E5%BD%A2ABCD%E4%B8%AD%2CM%E6%98%AFBC%E7%9A%84%E4%B8%AD%E7%82%B9%2CMN%E2%8A%A5AM%2CMN%E4%B8%8E%E2%88%A0DCE%E7%9A%84%E5%B9%B3%E5%88%86%E7%BA%BF%E7%9B%B8%E4%BA%A4%E4%BA%8EN%2CE%E5%9C%A8BC%E7%9A%84%E5%BB%B6%E9%95%BF%E7%BA%BF%E4%B8%8A%2C%E6%B1%82%E8%AF%81%EF%BC%9AAM%3DMN)
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