电路题,
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电路题,
电路题,
电路题,
左下红框用戴维南定理化简:
Us1 = 12 * 3 / 9 = 4 V
Rs1 = 6 // 3 = 2 Ω
左上红框转换成电压源:
Us2 = 2 * 4 = 8 V
Rs2 = 4 Ω
合并:
Us = Us1 + Us2 = 12 V
Rs = Rs1 + Rs2 + 6 = 12Ω
求左图 Uab:
I = 0 ,6I = 0
Uab = 12 V
求右图 Isc :
Isc * (12 + 12//6) + 6 * Isc * 12 / 18 = 12
Isc = 0.6 A
Rab = Uab / Isc = 2 Ω
U = - Uab * 4 / 6 = - 8 V