△ABC中,若sinA=二分之根号二,cotB=二分之一,则∠C=?请大哥们注意,是COT 不是COS!cotangent!
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![△ABC中,若sinA=二分之根号二,cotB=二分之一,则∠C=?请大哥们注意,是COT 不是COS!cotangent!](/uploads/image/z/9048295-55-5.jpg?t=%E2%96%B3ABC%E4%B8%AD%2C%E8%8B%A5sinA%3D%E4%BA%8C%E5%88%86%E4%B9%8B%E6%A0%B9%E5%8F%B7%E4%BA%8C%2CcotB%3D%E4%BA%8C%E5%88%86%E4%B9%8B%E4%B8%80%2C%E5%88%99%E2%88%A0C%3D%3F%E8%AF%B7%E5%A4%A7%E5%93%A5%E4%BB%AC%E6%B3%A8%E6%84%8F%EF%BC%8C%E6%98%AFCOT+%E4%B8%8D%E6%98%AFCOS%EF%BC%81cotangent%21)
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