*(p=&n)=*pk*(*pm) #includemain(){int k=2,m=4,n=6,*pk=&k,*pm=&m,*p;*(p=&n)=*pk*(*pm);printf("%d\n",n);}上面是C语言源程序现在*pk=&k即为*pk代表的是k的地址*pm=&m代表的是m变量的地址在运算*pk*(*pm)时,不就是k和m的地址
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/03 12:25:18
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