VmLAl2(SO4)3溶液中含有Al3+mg,取V/2mL该溶液用水稀释至3VmL,则SO42-物质的量浓度
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![VmLAl2(SO4)3溶液中含有Al3+mg,取V/2mL该溶液用水稀释至3VmL,则SO42-物质的量浓度](/uploads/image/z/9312070-22-0.jpg?t=VmLAl2%28SO4%293%E6%BA%B6%E6%B6%B2%E4%B8%AD%E5%90%AB%E6%9C%89Al3%2Bmg%2C%E5%8F%96V%2F2mL%E8%AF%A5%E6%BA%B6%E6%B6%B2%E7%94%A8%E6%B0%B4%E7%A8%80%E9%87%8A%E8%87%B33VmL%2C%E5%88%99SO42-%E7%89%A9%E8%B4%A8%E7%9A%84%E9%87%8F%E6%B5%93%E5%BA%A6)
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VmLAl2(SO4)3溶液中含有Al3+mg,取V/2mL该溶液用水稀释至3VmL,则SO42-物质的量浓度
VmLAl2(SO4)3溶液中含有Al3+mg,取V/2mL该溶液用水稀释至3VmL,则SO42-物质的量浓度
VmLAl2(SO4)3溶液中含有Al3+mg,取V/2mL该溶液用水稀释至3VmL,则SO42-物质的量浓度
n(Al3+) = mg/27g/mol = 0.037mol
c(Al3+) = 0.037mol /VmL = 37/V mol/L
则原溶液中硫酸根的浓度为:c(SO42-) = 3/2 *c(Al3+)
取一半原溶液稀释到3VmL,相当于把溶液稀释6倍,所以得到的硫酸的浓度:
c(SO42-) = 3/2 *c(Al3+) * 1/6 = 3/2 * 37/V mol/L * 1/6 = 37/4V mol/L