(1/2)∫dx/(tan(x/2)cos^2(x/2))求这个的积分,还是不是很懂,为什么将tanx/2视为中间变量,其导数刚好是1/2cos^2(x/2))
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![(1/2)∫dx/(tan(x/2)cos^2(x/2))求这个的积分,还是不是很懂,为什么将tanx/2视为中间变量,其导数刚好是1/2cos^2(x/2))](/uploads/image/z/9318417-33-7.jpg?t=%281%2F2%29%E2%88%ABdx%2F%28tan%28x%2F2%29cos%5E2%28x%2F2%29%29%E6%B1%82%E8%BF%99%E4%B8%AA%E7%9A%84%E7%A7%AF%E5%88%86%2C%E8%BF%98%E6%98%AF%E4%B8%8D%E6%98%AF%E5%BE%88%E6%87%82%EF%BC%8C%E4%B8%BA%E4%BB%80%E4%B9%88%E5%B0%86tanx%2F2%E8%A7%86%E4%B8%BA%E4%B8%AD%E9%97%B4%E5%8F%98%E9%87%8F%2C%E5%85%B6%E5%AF%BC%E6%95%B0%E5%88%9A%E5%A5%BD%E6%98%AF1%2F2cos%5E2%28x%2F2%29%29)
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(1/2)∫dx/(tan(x/2)cos^2(x/2))求这个的积分,还是不是很懂,为什么将tanx/2视为中间变量,其导数刚好是1/2cos^2(x/2))
(1/2)∫dx/(tan(x/2)cos^2(x/2))
求这个的积分,
还是不是很懂,为什么将tanx/2视为中间变量,其导数刚好是1/2cos^2(x/2))
(1/2)∫dx/(tan(x/2)cos^2(x/2))求这个的积分,还是不是很懂,为什么将tanx/2视为中间变量,其导数刚好是1/2cos^2(x/2))
(1/2)∫dx/(tan(x/2)cos^2(x/2))
=∫d(1/2x)/(tan(x/2)cos^2(x/2))
设x=x/2
原式=∫dx/(tanxcos^2x)
=∫dx/((sinx/cosx)cos^2x)
=∫dx/(sinxcosx)
=∫(sin^2x+cos^2x)dx/(sinxcosx)
=∫(sinx/cosx)dx+∫(cosx/sinx)dx+C
=∫d(cosx)/cosx-∫d(sinx)/sinx+C
=ln(cosx/sinx)+C=lncotx +C
用凑微分法,
将tanx/2视为中间变量,其导数刚好是1/2cos^2(x/2))
积分结果就是1/2*ln(tanx/2)+c
希望对你有帮助!
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