第一题选A,第二题选B,(1)已知动点P(cosθ,sinθ),其中π/2≤θ≤3π/2,定点Q(2,0),直线l:x+y=2,线段PQ绕点Q顺时针旋转90°到RQ,直线l绕点Q逆时针旋转90°得直线m,则动点R到直线m的最小距离为:A:√2/2、B:
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![第一题选A,第二题选B,(1)已知动点P(cosθ,sinθ),其中π/2≤θ≤3π/2,定点Q(2,0),直线l:x+y=2,线段PQ绕点Q顺时针旋转90°到RQ,直线l绕点Q逆时针旋转90°得直线m,则动点R到直线m的最小距离为:A:√2/2、B:](/uploads/image/z/9480339-27-9.jpg?t=%E7%AC%AC%E4%B8%80%E9%A2%98%E9%80%89A%2C%E7%AC%AC%E4%BA%8C%E9%A2%98%E9%80%89B%2C%281%29%E5%B7%B2%E7%9F%A5%E5%8A%A8%E7%82%B9P%28cos%CE%B8%2Csin%CE%B8%29%2C%E5%85%B6%E4%B8%AD%CF%80%2F2%E2%89%A4%CE%B8%E2%89%A43%CF%80%2F2%2C%E5%AE%9A%E7%82%B9Q%282%2C0%29%2C%E7%9B%B4%E7%BA%BFl%3Ax%2By%3D2%2C%E7%BA%BF%E6%AE%B5PQ%E7%BB%95%E7%82%B9Q%E9%A1%BA%E6%97%B6%E9%92%88%E6%97%8B%E8%BD%AC90%C2%B0%E5%88%B0RQ%2C%E7%9B%B4%E7%BA%BFl%E7%BB%95%E7%82%B9Q%E9%80%86%E6%97%B6%E9%92%88%E6%97%8B%E8%BD%AC90%C2%B0%E5%BE%97%E7%9B%B4%E7%BA%BFm%2C%E5%88%99%E5%8A%A8%E7%82%B9R%E5%88%B0%E7%9B%B4%E7%BA%BFm%E7%9A%84%E6%9C%80%E5%B0%8F%E8%B7%9D%E7%A6%BB%E4%B8%BA%EF%BC%9AA%3A%E2%88%9A2%2F2%E3%80%81B%EF%BC%9A)
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