作业帮x²+xy+y²可以替换成别的代数式吗是一道题目.(x²+xy+y²)(x²-xy+y²)-(x²+y²)²稍微详细点恩,,我们老师不允许我们跳步骤,
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x²+xy+y²可以替换成别的代数式吗是一道题目.(x²+xy+y²)(x²-xy+y²)-(x²+y²)²稍微详细点恩,,我们老师不允许我们跳步骤,
x²+xy+y²可以替换成别的代数式吗
是一道题目.
(x²+xy+y²)(x²-xy+y²)-(x²+y²)²
稍微详细点恩,,我们老师不允许我们跳步骤,
x²+xy+y²可以替换成别的代数式吗是一道题目.(x²+xy+y²)(x²-xy+y²)-(x²+y²)²稍微详细点恩,,我们老师不允许我们跳步骤,
(x²+xy+y²)(x²-xy+y²)-(x²+y²)²
=(x²+y²)²-x²y²-(x²+y²)²
=-x²y²
.
(x²+xy+y²)(x²-xy+y²)-(x²+y²)²
=(x²+y²)² -y²y²
=-(x²+y²)²
=y4
x²+xy+y²可以替换成别的代数式吗是一道题目.(x²+xy+y²)(x²-xy+y²)-(x²+y²)²稍微详细点恩,,我们老师不允许我们跳步骤,
0.5x²+xy+0.5y²
因式分解：x²-xy-12y²
4x²y-xy²
-9x²-y²+6xy
x²-2xy+y²-9
6xy²-9x²y-y²因式分解
若x²+xy-2y²=0,则x²+3xy+y²/x²+y²
x²+xy-2y²=0则x²+3xy+y²/x²+y²
因式分解 x²-2xy+y²-z²
计算：4xy²-3x²y-{3x²y-[2xy²-4x²y+2(x²y-2xy²)]急
（x²+y²)²-x²y²=(x²+y²)²-(xy)²=(x²+y²+xy)(x²+y²-xy)=(x+y)²(x-y)²-xy+xy=(x+y)²(x-y)²
x²-4y²/x²+2xy+y²÷x+2y/2x²+2xy
x²y²-x²y-xy²+x+y-1因式分解
已知x²y²+x²+y²=10xy-16 求x,y
计算x²-x/x²×x/1-x和x²-4y²/x²+2xy+y²÷x+2y/x²+xy
x²-y²+6x+9分之x²+y²-9-2xy
3x²-y²=8x²＋xy＋y²=4