正三棱柱ABC-A1B1C1,D是A1C1的中点求证【1】平面AB1D⊥平面AA1CC1【2】已知A1B1=2,AA1=6,求BC1到平面AB1D的距离
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![正三棱柱ABC-A1B1C1,D是A1C1的中点求证【1】平面AB1D⊥平面AA1CC1【2】已知A1B1=2,AA1=6,求BC1到平面AB1D的距离](/uploads/image/z/9497051-35-1.jpg?t=%E6%AD%A3%E4%B8%89%E6%A3%B1%E6%9F%B1ABC-A1B1C1%2CD%E6%98%AFA1C1%E7%9A%84%E4%B8%AD%E7%82%B9%E6%B1%82%E8%AF%81%E3%80%901%E3%80%91%E5%B9%B3%E9%9D%A2AB1D%E2%8A%A5%E5%B9%B3%E9%9D%A2AA1CC1%E3%80%902%E3%80%91%E5%B7%B2%E7%9F%A5A1B1%EF%BC%9D2%2CAA1%EF%BC%9D6%2C%E6%B1%82BC1%E5%88%B0%E5%B9%B3%E9%9D%A2AB1D%E7%9A%84%E8%B7%9D%E7%A6%BB)
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