matlab方程表达式函数h=6.76*(2.2*10.^(-8)).^0.53*0.08.^0.75*(2.27*10.^11).^(-0.06)*((pi*960)/(30*cos(15))).^0.75*(66.58*sin(20)+(x(1,:)./2)*(1-(x(1,:)).^(-1))).^0.75*(((66.58*sin(20)+x(1,:))+(66.58*sin(20)-x(1,:)))/(66.58*2*sin(20)*(cos(16)).^2
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![matlab方程表达式函数h=6.76*(2.2*10.^(-8)).^0.53*0.08.^0.75*(2.27*10.^11).^(-0.06)*((pi*960)/(30*cos(15))).^0.75*(66.58*sin(20)+(x(1,:)./2)*(1-(x(1,:)).^(-1))).^0.75*(((66.58*sin(20)+x(1,:))+(66.58*sin(20)-x(1,:)))/(66.58*2*sin(20)*(cos(16)).^2](/uploads/image/z/955351-55-1.jpg?t=matlab%E6%96%B9%E7%A8%8B%E8%A1%A8%E8%BE%BE%E5%BC%8F%E5%87%BD%E6%95%B0h%3D6.76%2A%282.2%2A10.%5E%28-8%29%29.%5E0.53%2A0.08.%5E0.75%2A%282.27%2A10.%5E11%29.%5E%28-0.06%29%2A%28%28pi%2A960%29%2F%2830%2Acos%2815%29%29%29.%5E0.75%2A%2866.58%2Asin%2820%29%2B%28x%281%2C%3A%29.%2F2%29%2A%281-%28x%281%2C%3A%29%29.%5E%28-1%29%29%29.%5E0.75%2A%28%28%2866.58%2Asin%2820%29%2Bx%281%2C%3A%29%29%2B%2866.58%2Asin%2820%29-x%281%2C%3A%29%29%29%2F%2866.58%2A2%2Asin%2820%29%2A%28cos%2816%29%29.%5E2)
matlab方程表达式函数h=6.76*(2.2*10.^(-8)).^0.53*0.08.^0.75*(2.27*10.^11).^(-0.06)*((pi*960)/(30*cos(15))).^0.75*(66.58*sin(20)+(x(1,:)./2)*(1-(x(1,:)).^(-1))).^0.75*(((66.58*sin(20)+x(1,:))+(66.58*sin(20)-x(1,:)))/(66.58*2*sin(20)*(cos(16)).^2
matlab方程表达式
函数h=6.76*(2.2*10.^(-8)).^0.53*0.08.^0.75*(2.27*10.^11).^(-0.06)*((pi*960)/(30*cos(15))).^0.75*(66.58*sin(20)+(x(1,:)./2)*(1-(x(1,:)).^(-1))).^0.75*(((66.58*sin(20)+x(1,:))+(66.58*sin(20)-x(1,:)))/(66.58*2*sin(20)*(cos(16)).^2)).^0.41*w.^(-0.16)
出现错误
Error using *
Inner matrix dimensions must agree.
Error in sx (line 5)
h=6.76*(2.2*10.^(-8)).^0.53*0.08.^0.75*(2.27*10.^11).^(-0.06)*((pi*960)/(30*cos(15))).^0.75*(66.58*sin(20)+(x(1,:)./2)*(1-(x(1,:)).^(-1))).^0.75*(((66.58*sin(20)+x(1,:))+(66.58*sin(20)-x(1,:)))/(66.5 .是怎么回事啊 再者x=-35:35 在函数中用x(1,:)表示说对吗
matlab方程表达式函数h=6.76*(2.2*10.^(-8)).^0.53*0.08.^0.75*(2.27*10.^11).^(-0.06)*((pi*960)/(30*cos(15))).^0.75*(66.58*sin(20)+(x(1,:)./2)*(1-(x(1,:)).^(-1))).^0.75*(((66.58*sin(20)+x(1,:))+(66.58*sin(20)-x(1,:)))/(66.58*2*sin(20)*(cos(16)).^2
中间还有几个乘号也加点试试呗
x=-35:35 在函数中用x(1,:)表示是可以的
ps.你的程序可读性差了点吧……