已知圆C:(x+1)^2+(y-2)^2=25,直线L:(2m+1)x+(m+1)y-7m-4=0证明:无论m取什么实数,直线L与圆恒交于亮点
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![已知圆C:(x+1)^2+(y-2)^2=25,直线L:(2m+1)x+(m+1)y-7m-4=0证明:无论m取什么实数,直线L与圆恒交于亮点](/uploads/image/z/959017-49-7.jpg?t=%E5%B7%B2%E7%9F%A5%E5%9C%86C%EF%BC%9A%28x%2B1%29%5E2%2B%28y-2%29%5E2%3D25%2C%E7%9B%B4%E7%BA%BFL%EF%BC%9A%282m%2B1%29x%2B%28m%2B1%29y-7m-4%3D0%E8%AF%81%E6%98%8E%EF%BC%9A%E6%97%A0%E8%AE%BAm%E5%8F%96%E4%BB%80%E4%B9%88%E5%AE%9E%E6%95%B0%2C%E7%9B%B4%E7%BA%BFL%E4%B8%8E%E5%9C%86%E6%81%92%E4%BA%A4%E4%BA%8E%E4%BA%AE%E7%82%B9)
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