已知x-2y=2014,求 [(3x+2y)(3x-2y)-(x+2y)×(5x-2y)]÷8x的值
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已知x-2y=2014,求 [(3x+2y)(3x-2y)-(x+2y)×(5x-2y)]÷8x的值
已知x-2y=2014,求 [(3x+2y)(3x-2y)-(x+2y)×(5x-2y)]÷8x的值
已知x-2y=2014,求 [(3x+2y)(3x-2y)-(x+2y)×(5x-2y)]÷8x的值
答:
x-2y=2014
[(3x+2y)(3x-2y)-(x+2y)×(5x-2y)]÷8x
=[9x²-4y²-(5x²+8xy-4y²)]÷(8x)
=(4x²-8xy)÷(8x)
=(x-2y)/2
=2014/2
=1007
[(3x+2y)(3x-2y)-(x+2y)(5x-2y)]÷8x
=[(9x²-4y²)-(5x²+8xy-4y²)]÷8x
=(9x²-4y²-5x²-8xy+4y²)÷8x
=(4x²-8xy)÷8x
=[8x(2分之1x-y)]÷8x
=2分之1x-y
=2分之1(x-2y)
=2分之1×2014
=1007
先计算(3x+2y)(3x-2y)-(x+2y)×(5x-2y)
=9x^2-4y^2-5x^2+4y^2-8xy
=4x^2-8xy
除以8x后,
=(x-2y)/2=2014/4=1007
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