讨论以下函数在x=0处的连续性x>0时,f(x)={[1+(1/x)]^(1/x)/e}^(1/x)x0时,f(x)={[1+x]^(1/x)/e}^(1/x)x≤0时,f(x)=e^(-1/2)
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/09 08:03:20
![讨论以下函数在x=0处的连续性x>0时,f(x)={[1+(1/x)]^(1/x)/e}^(1/x)x0时,f(x)={[1+x]^(1/x)/e}^(1/x)x≤0时,f(x)=e^(-1/2)](/uploads/image/z/9772907-59-7.jpg?t=%E8%AE%A8%E8%AE%BA%E4%BB%A5%E4%B8%8B%E5%87%BD%E6%95%B0%E5%9C%A8x%3D0%E5%A4%84%E7%9A%84%E8%BF%9E%E7%BB%AD%E6%80%A7x%3E0%E6%97%B6%2Cf%28x%29%3D%7B%5B1%2B%281%2Fx%29%5D%5E%281%2Fx%29%2Fe%7D%5E%281%2Fx%29x0%E6%97%B6%EF%BC%8Cf%28x%29%3D%7B%5B1%2Bx%5D%5E%281%2Fx%29%2Fe%7D%5E%281%2Fx%29x%E2%89%A40%E6%97%B6%EF%BC%8Cf%28x%29%3De%5E%28-1%2F2%29)
xUmkP+d1Ft0؊l_.!|ZۡtMfWlmT&~_InLFڏcɹ999܄a2}<8.IoRi i1_TZ>{#,|
%m0uQbi67xQcSʇ!Le&EáJq
Zm>K6agNFLwyN`JԎmmrFLqO+eKO=k2J!I<{ A