动能定理运用时,何时运用整个过程来解题?有没有条件限制?诸如:这个人跳水,求阻力所做功?如果不考虑整个过程,就要分为两个阶段,向上阶段,wf1-mgh0A=1/2mvA^2-0 向下阶段,wf2+mghAB=1/2mVB^2-1/2mV
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![动能定理运用时,何时运用整个过程来解题?有没有条件限制?诸如:这个人跳水,求阻力所做功?如果不考虑整个过程,就要分为两个阶段,向上阶段,wf1-mgh0A=1/2mvA^2-0 向下阶段,wf2+mghAB=1/2mVB^2-1/2mV](/uploads/image/z/9795076-52-6.jpg?t=%E5%8A%A8%E8%83%BD%E5%AE%9A%E7%90%86%E8%BF%90%E7%94%A8%E6%97%B6%2C%E4%BD%95%E6%97%B6%E8%BF%90%E7%94%A8%E6%95%B4%E4%B8%AA%E8%BF%87%E7%A8%8B%E6%9D%A5%E8%A7%A3%E9%A2%98%3F%E6%9C%89%E6%B2%A1%E6%9C%89%E6%9D%A1%E4%BB%B6%E9%99%90%E5%88%B6%3F%E8%AF%B8%E5%A6%82%EF%BC%9A%E8%BF%99%E4%B8%AA%E4%BA%BA%E8%B7%B3%E6%B0%B4%2C%E6%B1%82%E9%98%BB%E5%8A%9B%E6%89%80%E5%81%9A%E5%8A%9F%3F%E5%A6%82%E6%9E%9C%E4%B8%8D%E8%80%83%E8%99%91%E6%95%B4%E4%B8%AA%E8%BF%87%E7%A8%8B%2C%E5%B0%B1%E8%A6%81%E5%88%86%E4%B8%BA%E4%B8%A4%E4%B8%AA%E9%98%B6%E6%AE%B5%2C%E5%90%91%E4%B8%8A%E9%98%B6%E6%AE%B5%2Cwf1-mgh0A%3D1%2F2mvA%5E2-0+++++%E5%90%91%E4%B8%8B%E9%98%B6%E6%AE%B5%2Cwf2%2BmghAB%3D1%2F2mVB%5E2-1%2F2mV)
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