如图,BE=DC,AB=AD,AE=AC,角1=35度,则角2＝＿＿＿＿．若点D恰好落在BE上,则角3＝＿＿＿＿下面还有条线CA!

如图,已知：AB⊥AC,AD⊥AE,AB=AC,AD=AE,说明BE=DC的理由 如图,在四边形ABCD中,AB=DC,延长线段CB到E,是BE=AD,连接AE,AC,AE=AC,求证:AD‖EC 如图,在四边形ABCD中,AB=DC,延长线段CB到E,是BE=AD,连接AE、AC,AE=AC,求证：AD‖EC 如图,点C在线段BE上,AB⊥AC,AD⊥AE,且AD=AE,连接CD,试说明DC⊥BE 如图已知AB=AC,AD=AE,DC,BE交于点O,求证AO平分∠BAC 如图,AB=AC,AD=AE,AB,DC相交于点M,AC,BE相交于点N,AD//BE,AE//DC,求证∠DAB=∠EAC DA⊥AB EA ⊥AC AB=AD AC=AE 求证 DC=BE 如图,已知AD⊥AB,AC⊥AE,AD=AB,角C=角E,证明:DC⊥BE. 如图所示,已知AB⊥AC,AD⊥AE,AB=AC,AD=AE,求证：BE=DC 已知AD⊥AB,AE⊥AC,AD=AB,AE=AC,求证BE=DC 如图所示,已知AB⊥AC,AD⊥AE,AB=AC,AD=AE,求证：BE=DC非常急 已知如图DA垂直于AB,EA垂直于AC,AB=AD,AC=AE求DC=BEDG垂直BE 已知:如图AB=AC,AD=AE.AB,DC相交于点M,AC,BE相交于点N, 1.如图,在△ABE和△ACD中,AB=AC,AD=AE,AD垂直AE,AD垂直DC,AE垂直BE.求证：CD=BE 如图,AB⊥AC,AD⊥AE,AB=AC,AD=AE.求证BE⊥CD 如图,AB⊥AC,AD⊥AE,AB=AC,AD=AE.求证BE⊥CD 已知AD⊥AB,AC⊥AE,且AD=AB,AC=AE.求证：DC⊥BE,DC=BE. 如图,已知△ABC中,AE=BE=AC,AD平分∠BAC,DC⊥AC求证：DE是AB的中垂线