如图,已知AB平行于CD,AD与BC交于点O,若AD:BC=5:4,BO.=1,DO=2.5,那么AD=?
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![如图,已知AB平行于CD,AD与BC交于点O,若AD:BC=5:4,BO.=1,DO=2.5,那么AD=?](/uploads/image/z/9962630-62-0.jpg?t=%E5%A6%82%E5%9B%BE%2C%E5%B7%B2%E7%9F%A5AB%E5%B9%B3%E8%A1%8C%E4%BA%8ECD%2CAD%E4%B8%8EBC%E4%BA%A4%E4%BA%8E%E7%82%B9O%2C%E8%8B%A5AD%3ABC%3D5%3A4%2CBO.%3D1%2CDO%3D2.5%2C%E9%82%A3%E4%B9%88AD%3D%3F)
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如图,已知AB平行于CD,AD与BC交于点O,若AD:BC=5:4,BO.=1,DO=2.5,那么AD=?
如图,已知AB平行于CD,AD与BC交于点O,若AD:BC=5:4,BO.=1,DO=2.5,那么AD=?
如图,已知AB平行于CD,AD与BC交于点O,若AD:BC=5:4,BO.=1,DO=2.5,那么AD=?
设OA为x,OC为y,根据题意有(x+2.5):(1+y)=5:4
∵AB∥CD ∴△AOB∽△DOC ∴OA:OD=OB:OC 即x:2.5=1:y
联立方程组,解得 x=1.25 AD=x+2.5=3.75
3.75