2(x²-xy)-3(2x²-3xy)-2[x²-(2x²-xy+y²]=?
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整式乘法..1.3xy(x²y-xy²+xy)-xy²(2x²-xy+2x)2.(x-1)(x²-4x+3)-x(x²-5x+2)
2(x²-xy)-3(2x²-3xy)-2[x²-(2x²-xy+y²]=?
若x²+xy-2y²=0,则x²+3xy+y²/x²+y²
x²+xy-2y²=0则x²+3xy+y²/x²+y²
(xy-x²)÷[(x²-2xy+y²)÷xy]*[(x-y)÷x²]
3x²y-[2xy²-2(xy-1.5x²y)+xy]+3xy² 其中x=3 y=-三分之一(需要解题过程)
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