2(x²-xy)-3(2x²-3xy)-2[x²-(2x²-xy+y²]=?

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2(x²-xy)-3(2x²-3xy)-2[x²-(2x²-xy+y²]=?
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2(x²-xy)-3(2x²-3xy)-2[x²-(2x²-xy+y²]=?
2(x²-xy)-3(2x²-3xy)-2[x²-(2x²-xy+y²]=?

2(x²-xy)-3(2x²-3xy)-2[x²-(2x²-xy+y²]=?
2(x²-xy)-3(2x²-3xy)-2[x²-(2x²-xy+y²)]
=2x²-2xy-6x²+9xy-2x²+4x²-2xy+2y²
=(2-6-2+4)x²+(-2+9-2)xy+2y²
=-2x²+5xy+2y²

直接拆开啊
-2x²+9xy-2y²

5xy-2x²+2y²