若x1满足2x+2^x=5,x2满足2x+2log2(x+1)=5,求x1+x2=多少?2X+2^x=5x+2^(x-1)=2.52X+2log2(x-1)(2是底数)=5x+log2(x-1)=2.5其中y=2^(x-1)与y=log2(x-1)关于y=x-1对称y=2.5-x与前面指数对数曲线交点即为x1,x2.x1+x2为y=2.5-x,y=x-1交点

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