若x1、x2、都满足|2x-1|+|2x+3|=4,且x1<x2,则x1-x2的取值范围是?
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若x1、x2、都满足|2x-1|+|2x+3|=4,且x1<x2,则x1-x2的取值范围是?
若x1、x2、都满足|2x-1|+|2x+3|=4,且x1<x2,则x1-x2的取值范围是?
若x1、x2、都满足|2x-1|+|2x+3|=4,且x1<x2,则x1-x2的取值范围是?
由|2x-1|+|2x+3|=2得|x-1/2|+|x-(-3/2)|=2,从图像上来说,它代表的是数轴上到点1/2与-3/2的距离之和等于2的点的轨迹.
已知点1/2与-3/2的距离就是2,所以点x的轨迹是1/2与-3/2之间的线段.所以x1与x2之间的距离|x1-x2|的最大值就是2,所以|x1-x2|≤2,又x1<x2,所以-2≤x1-x2<0
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