若x1满足2x+2^x=5,x2满足2x+log2(x-1)=5,则x1+x2=?这样可以化简到 2^(x1-1)=1.5-(x1-1)log2(x2-1)=1.5-(x2-1)因为y=2^x与y=log2(x)互为反函数 为什么有x1-1+x2-1=1.
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![若x1满足2x+2^x=5,x2满足2x+log2(x-1)=5,则x1+x2=?这样可以化简到 2^(x1-1)=1.5-(x1-1)log2(x2-1)=1.5-(x2-1)因为y=2^x与y=log2(x)互为反函数 为什么有x1-1+x2-1=1.](/uploads/image/z/10255438-46-8.jpg?t=%E8%8B%A5x1%E6%BB%A1%E8%B6%B32x%2B2%5Ex%3D5%2Cx2%E6%BB%A1%E8%B6%B32x%2Blog2%28x-1%29%3D5%2C%E5%88%99x1%2Bx2%3D%3F%E8%BF%99%E6%A0%B7%E5%8F%AF%E4%BB%A5%E5%8C%96%E7%AE%80%E5%88%B0+2%5E%28x1-1%29%3D1.5-%28x1-1%29log2%28x2-1%29%3D1.5-%28x2-1%29%E5%9B%A0%E4%B8%BAy%3D2%5Ex%E4%B8%8Ey%3Dlog2%28x%29%E4%BA%92%E4%B8%BA%E5%8F%8D%E5%87%BD%E6%95%B0+%E4%B8%BA%E4%BB%80%E4%B9%88%E6%9C%89x1-1%2Bx2-1%3D1.)
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若x1满足2x+2^x=5,x2满足2x+log2(x-1)=5,则x1+x2=?这样可以化简到 2^(x1-1)=1.5-(x1-1)log2(x2-1)=1.5-(x2-1)因为y=2^x与y=log2(x)互为反函数 为什么有x1-1+x2-1=1.
若x1满足2x+2^x=5,x2满足2x+log2(x-1)=5,则x1+x2=?
这样可以化简到 2^(x1-1)=1.5-(x1-1)
log2(x2-1)=1.5-(x2-1)
因为y=2^x与y=log2(x)互为反函数 为什么有x1-1+x2-1=1.
若x1满足2x+2^x=5,x2满足2x+log2(x-1)=5,则x1+x2=?这样可以化简到 2^(x1-1)=1.5-(x1-1)log2(x2-1)=1.5-(x2-1)因为y=2^x与y=log2(x)互为反函数 为什么有x1-1+x2-1=1.
反函数就是把x和y交换了
所以2^x中的x的值和y=log2(x)中的y值是相等的
所以x2-1=1.5-(x1-1)
x1-1=1.5(x2-1)
同时成立
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