设f(x)在[a,b]上连续可导,a>0 .证明：存在ξ,η∈(a,b),使得f'(ξ)=[(a+b)/2η]f‘(η)RT

设函数f(x)在[a,b]上连续,在(a,b)可导,且f(a)*f(b)>0,f(a)*f((a+b)/2) 设函数f(x)在[a,b]上连续,(a,b)可导,且f(a)=0,证明至少存在一点ξ∈(a设函数f(x)在[a,b]上连续,(a,b)可导,且f(a)=0,证明至少存在一点ξ∈(a,b),使得f(ξ)=(b-ξ)*f'(ξ) 设f(x)在[a,b]上连续,且a 设函数f(x)在[a,b]上连续,a 设f(x)在[a,b]上连续,且a 设f(x)在[a,b]上连续,且a 设f(x)在[a,b]上连续,a 设函数f(x)在[a,b]上连续,a 设f(x)在(a,b)内连续可导f'(x) 设f(x)在区间[a,b]连续,在（a,b)可导,那么f(x)的导数在区间（a,b)上的导数是否连续?怎么证明?或反例?设f(x)在区间[a,b]连续，在（a,b)可导，那么f(x)的导数在区间（a,b)上的导数是否有界？怎么证 ◆微积分 证明 设f(x)在[a,b]连续,在(a,b)可导,f(a) = 0... 设f(x)在[a,b]连续,在(a,b)可导,f'(x)≤0,F(x)=[∫(a→x)f(t)dt]/(x-a),证明在(a,b)有F'(x)≤0 证明:设f(x)在[a,b]上连续,在(a,b)内可导,(0 设f(x)在[a,b]上连续,在(a,b)上可导(0 设函数f(x)在[a,b]上连续,在(a,b)内可导(0 设f(x)在[a,b]上连续,在(a,b)内可导,(0 设f(x)在[a,b]上连续,在(a,b)内可导(0 设f(x)在[a,b]上连续,在(a,b)内可导(0