.若实数x,y满足x｜x｜－y｜y｜＝1,则点(x,y)到直线y=x的距离的取值范围是

.若实数x,y满足x｜x｜－y｜y｜＝1,则点(x,y)到直线y=x的距离的取值范围是 若实数x,y满足y 若实数x,y满足不等式y 若实数xy满足x-y+1 若实数x,y是满足1 若实数x,y满足x-y+1》=0,x+y>=0,x 若实数x,y满足x-y+1>=0,x+y>=0,x 已知实数x,y满足x-y 已知实数X,Y满足{|x+y| 实数x,y满足:｜x+y｜ 若实数x,y满足x 若实数x,y满足x 若实数x,y满足x>=1,y>=1,x+y 已知实数x,y满足y=|x-1|若x+2y 若实数x,y满足x+y-4 若实数x,y满足不等式x-y>=-1,x+y>=1,3x-y 若实数x,y满足不等式x-y>=-1,x+y>=1,3x-y 若正实数x,y满足x+y+1/x+1/y=5,则x+y的最大值是多少