计算：1 (log4 3+log8 3)log3 2 2 loga b×logb c×logc a

计算log9(根号2)*[log4(3)+log8(3)] 计算:(log4 3+log8 3)×log9 √2=? 计算：1 (log4 3+log8 3)log3 2 2 loga b×logb c×logc a log4(3)+log8(3) 怎么算 log4(3)+log8(3) 怎么相加? (log4(3)+log8(3))*log3(2) 计算（log4 3+ log8 3）（log3 2+ log9 2）-- log1/2 32^(1/3)+5^（log259） (log4^3+log8^3)(log3^2+log9^2)详细计算过程.~ log4(3)-log4(12)-log8(4) =log4(3/12)- log8( 8^(2/3) ) log8( 8^(2/3) )怎么得出来的? [log4(3)+log8(3)]*log3(2)答案是1/3么 (log3^2 + log9^4)×(log4^3 + log8^3) (log3 2+log9 2)*(log4 3+log8 3)求值 化简(log4(3)+log8(3))(log3(2)+log9(2)) 求值:(log4^ 3+log8 ^9)*(log3^ 2+log9 ^16) 计算（log2 3+log4 9+log8 27+……+log2^n 3^n）log9 n次根号3计算（log2 3+log4 9+log8 27+……+log2^n 3^n）log9 n次根号32 (log4(3)+log8(3))*(log3(2)+log8(2))-log1/2(^4√32)=?.. (log4(3)+log8(3))(log3(2)+log9(2))-log4(3)×log1/3(四次根号32) 1把loga^b表示成以b为底的对数2把loga^nb^n表示成以a为底的对数计算 log4^32 log9^8 * lg32^27log4^27/log4^3 (log4^3+log8^3)(log3^2+log9^2)