y=3^[log2(x^2+3x-4)]的单调递减区间2为底
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y=log2(x^2-2x-3) (4
求y=log2^x(log2^4x^2)+3的值域
log2 (x + 3) + log2(x + 2) = 1log2 (x + 3) + log2(x + 2) = 1
函数y=log2(x)+1按向量a平移可得到y=log2(2x-3)+4,则a
求y=log2(3-2x-x^2)值域
[log2 1]+[log2 2]+[log2 3]+[log2 4]+[log2 5]+...+[log2 1024]=?[x]表示不超过x的最大整数2为底 答案是8204
1.y=log0.5(-x^2+2x+3)2.y=[log2(x)]^2-3log2(x)+2
求y=(log2 x-2)(1/2 log2 x-3)(2
log2(4^x+4)=x+log2(2^x+1-3)log2(4^x+4)=x+log2[2^(x+1)-3]
|[log2(x)]^2-3log2(x)+1|
求函数y=(log2(x/3))(log2(x/4))在区间《2√2,8》上的最值
y=log2^(x+1) 3
y=log2|x+3|图像
y=log2(3-x)的定义域
求解log2(3x)=log2(2x+1)
求值域 y=4^x+2^x+1 +2 y=log2(x)+log2(8x^2) y=sinx-1/3sinx+1求值域 y=4^x+2^x+1 +2 y=log2(x)+log2(8x^2) y=sinx-1/3sinx+1
解方程log2(x+14)-log2(x+6)=3-log2(x+2)
求导 y=log2(x^2)-log2(x)