A={y|y=x^2-4x+3}={y|y大于或等于-1},解方程里答案不是这样,这里为什么会这样.B={s|s=-t^2-2t+2}={s|s小于或等于3},解方程里答案不是这样,这里为什么会这样.则A交B={X|-1小于或等于X小于或等于3}.原来这

(x-y) (x-2y)+(x+2y) (x-3y)-2(x-3y) (x-4y)= x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2 (x-2y)^5=a0(x+2y)^5+a1(x+2y)^4*y+a2(x+2y)^3*y^2+a3(x+2y)^2*y^3+a4(x+2y)y^4+a 2（x+y)-3(x-y)=3 ,4(x+y)+3(x-y)=15 {3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1 x+y/2+x-y/3=6,4(x+y)-3(x-y)=-20 {(x+y)/2+(x-y)/3=6 4(x+y)-3(x-y)=-20 4(x+y)-3(x-y)=-20,2/x+y+3/x-y=6 3(x+y)-2(x-y)=11 4(x+y)+3(x-y)=9 3(x+y)+2(x-y)=36 4(x+y)-5(x-y)=2 （x+y）/2- x-y/2=6 3(x+y)=4(x-y) x+y/3+x-y/2=6 4(x+y)-2(x-y)=40 4(x-y)-3(x-y)=9 5(x-y)+2(x-y)=11 3(x+y)-4(x-y)=11,2(x-y)+5(x+y)=27 先化简再求值(x-y)(x-2y)+(x-2y)(x-3y)-2(x-3y)(x-4y) x=4 y=5 如果A={（x,y）|x,y+2>0},B={（x,y）|2x+3y-6>0},C={（x,y）|x-4 x+y+2(-x-y+1)=3(1-y-x)-4-(y+x-1),x+y=? 已知2y-x=-3,求[4y(2x-y)-2x(2x-y)]/(2x-y