已知xy+x=-1,xy-y=-2,求代数式-x-[2y-2(xy+x)平方+3x]=+2[x+(xy-y)平方]的值,
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已知1/x+1/y=3,求分式(3x-3xy+3y)/(x+xy+y)的值我知道第一步是两边都乘以xy得x+y=3xy,然后怎么代进去,求回答!
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