1、f(x)=sin^2(x+π/4)-sin^2(x-π/4)的最小正周期是?2、已知sina=cos2a,π/2

已知函数f(x)=(1+1 anx)sin^2x+m sin(x+π/4)sin(x-π/4) f(x)=（1+cotx)sin^2x-2sin(x+π/4)sin(x-π/4)还有一题, 若f(x)=sin(π/4)x,求f(1)+f(2)+.+f(2010) 已知f(x)=cos^2x/1+sin^2x求f'(π/4)求导 傅里叶级数作图f（x）=2sin[x] - sin[2x] + 2/3sin[3x] - 1/2sin[4x]我用mathematica输入程序Plot[{2sin[x],-2sin[x],2sin[x] - sin[2x],-2sin[x] + sin[2x],2sin[x] - sin[2x] + 2/3sin[3x],-2sin[x] + sin[2x] - 2/3sin[3x],2sin[x] - sin[2x] + 2/3si 已知函数f(x)=4sinx-2/1+sin²x 证明f(x+2π)=f(x) f(x)=2sin(π/4 x+π/4) 计算f(1)+f(2)+f(3)+...f(2011) f(x)=sin(x+π/4)图像怎样变成F(x)=cos(2x) f(x)=sin(πx^2)(-1 函数f(x)=2sin(x+π/4)sin(x-π/4)+sin2x的值域 求f【x】=2sin[x+π/4]sin[x-π/4]+sin2x的最大值 证明∫( 0,π／2 ) (f sin x/(f sin x+f cos x) dx=π /4 f(x)=sin(2x+π/3)当tan(x+π/4)=1/3时,求f(x) 若f(x)=sin πx/6,则f(1)+f(2)+...+f(102)=? 化简f(x)=(1-√2*cos(2x-π/4))/sin(π/2-x) 化简f(x)=(1+√2*cos(2x-π/4))/sin(π/2-x) 函数f(x)=2sin(π/4-x)×cos(π/4+x)-1化简 已知函数 f(x)=sin^2(πx/4)-√3sin(πx/4)·cos(πx/4) (1)求f(x)最大值及此时x值 (2)求f(1)+f(2)+f(3)+已知函数 f(x)=sin^2(πx/4)-√3sin(πx/4)·cos(πx/4)(1)求f(x)最大值及此时x值(2)求f(1)+f(2)+f(3)+...+f(2010)值