log2底√1/48+log2底12-1/2log2底24等于?
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log2底√1/48+log2底12-1/2log2底24等于?
log2 SQR(7/48)+log2 12 -1/2log2 48
log2 SQR(7/48)+log2 12 -1/2log2 42
化简算式log2^√7/48+log2^12-1/2log2^42+1/2^log2^3
log2(√1/48)+log2 12-1/2log2 (24)-1/3
求值:log2√(7/48)+log2(12)-1/2log2(42)-1 这道题我算来算去算不对
计算log2 √(48/7)-log2 12+(1/2)log2 42-1
[log2 1]+[log2 2]+[log2 3]+[log2 4]+[log2 5]+...+[log2 1024]=?[x]表示不超过x的最大整数2为底 答案是8204
log2[√(7/48)]+log2(12)-log2(√42)
Log2√(7/48) +log2 12 -(1/2)log2 42要详细点的额
log2为底(x+1)
log2 1+ log2 2+ … + log2 n >= ⌊n/2」log2 (n/2) 求证明,2是底
1/2log2(7/48)+log2 12-1/2log2 42log2 的2 在g的右下脚
log2底根号5/56+log2(14)-1/2log2(35)答案是-1/2
log2(根号下7/48)+log2(12)-1/2log2(42)-1=?
log2根号7/48+log2^12-1/2log2^42-1=
log2底4/1为什么等于-2
log2底1等于0吗