已知:如图,在直角梯形ABCD中,AD‖BC,∠ABC=90°.点E是DC的中点,过点E作DC的垂线交AB于点P,交CB的延长线于点M.点F在线段ME上,且满足CF=AD,MF=MA.(1)若∠MFC=120°,求证:AM=2MB;(2)求证:∠MPB=90°-1/2∠FCM.

来源:学生作业帮助网 编辑:作业帮 时间:2024/08/31 05:49:56
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