lim(x→无穷)上面(3sinx+x^2cos1/x)下面(1+cosx)ln(x-1)
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lim(x→无穷)上面(3sinx+x^2cos1/x)下面(1+cosx)ln(x-1)
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求大一高数解答lim(根号下x^2+2x)-(根号下线x^2+1)=1(x趋近于正无穷)lim(sinx-xcosx)/x^2tanx=1/3(x趋近于0)lim(1+x)^1/x=1(x趋近于正无穷)希望高手给出过程~~上面已经有答案了~~谢谢~·