如图,AC=AB,AE=AD,∠EAB=∠DAC,求证：BD=CE

如图AB⊥AC,AD⊥AE,AB=AC,AD=AE.求证:△DAC≌三角形EAB 已知如图,AE=AC,∠E=∠C,∠EAB=∠CAD,求证:AB=AD 如图,AC=AB,AE=AD,∠EAB=∠DAC,求证：BD=CE 已知：如图,AE=AC,AB=AD,∠EAB=∠CAD 已知：如图,AE=AC,AB=AD,∠EAB=∠CAD已知：如图,AE=AC,AB=AD,∠EAB=∠CAD 求证：①△ABC全等于△ADE；②∠1=∠2 如图,AB⊥AC,AD⊥AE,AB=AC,AD=AE,求证:(1)△DAC≌△EAB;(2)BE⊥CD. ,の 如图,AB⊥AC,AD⊥AE,AB=AC,AD=AE,已知△DAC≌△EAB.求证BE⊥CD 已知：如图,AB⊥AC,AD⊥AE,AB=AC,AD=AE.求证：△DAC≌△EAB.可能不太好看， 已知:如图,AB=AC,AD=AE,角EAB=角DAC.求证:角D=角E. 已知:如图,AB=AC,AD=AE,角EAB=角DAC.角D=角E. 已知如图,AE=AC,AB=AD,∠EAB=∠CAD,试说明:∠B=∠D图： 如图,已知AB=AC,AE=AD,∠EAB=∠DAC,那么BE与CD相等吗?为什么? 如图,已知AB=AC,AE=AD,∠EAB=∠DAC,那么BE与CD相等吗,为什么 如图,在△ABC中,AB=AC,AD⊥BD,AE⊥CE,且AD=AE,BD和CE交于点O.说明∠EAB=∠DAC 如图,在△ABC中,AB=AC,AD⊥BD,AE⊥CE,且AD=AE,BD和CE交于点O.说明∠EAB=∠DAC的理由 如图,在△ABC中,AB=AC,AD⊥BD,AE⊥CE,且AD=AE,BD和CE相交于O,请说明∠EAB=∠DAC的理由. 如图:AB=AC,AD=AE,AB,DC相交于点M.AC,BE,相交于点N,∠DAC=∠EAB.求证:AM=AN 如图,AD,BD分别平分∠EAB和∠ABC,AE垂直EC于E,BC垂直EC于C.求证：AB=AE+BC 如图已知AD,BD分别平分∠EAB和∠CBA,EC过点D,AB=AE+BC,求证:AE平行BC