计算:(log4 9+log8 3)(log3 2+log9 2)-log1/3 4√81log后面的第一个数都是小数字,最后边是81的4次方根
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计算log9(根号2)*[log4(3)+log8(3)]
计算:(log4 3+log8 3)×log9 √2=?
求值:(log4^ 3+log8 ^9)*(log3^ 2+log9 ^16)
计算(log2 3+log4 9+log8 27+……+log2^n 3^n)log9 n次根号3计算(log2 3+log4 9+log8 27+……+log2^n 3^n)log9 n次根号32
(log8^27)/(log4^9)的值
log4(3)+log8(3) 怎么算
log4(3)+log8(3) 怎么相加?
(log4(3)+log8(3))*log3(2)
(log4^3+log8^3)(log3^2+log9^2)详细计算过程.~
计算:1 (log4 3+log8 3)log3 2 2 loga b×logb c×logc a
已知4^a=3 代数式log8(9)-2^(log4(3))用a表示为
log3 4×log4 8×log8 a=log根号3 9,则a=
log4(3)-log4(12)-log8(4) =log4(3/12)- log8( 8^(2/3) ) log8( 8^(2/3) )怎么得出来的?
计算(log4 3+ log8 3)(log3 2+ log9 2)-- log1/2 32^(1/3)+5^(log259)
(log3^2 + log9^4)×(log4^3 + log8^3)
(log3 2+log9 2)*(log4 3+log8 3)求值
化简(log4(3)+log8(3))(log3(2)+log9(2))
(log4(3)+log8(3))*(log3(2)+log8(2))-log1/2(^4√32)=?..