Sn=n(2n-1)an a1=1/3求数列的Sn,an
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/05 04:20:01
xRKN0Jh&%XX\TEj
jEY
$t+0P8fޛjXf\N", F~6g#ьF(Nɨ-oY<)[1-jg?>NSO(
|ѶhY%fr!]dqD[
Y`9NL%(@W4X=}_Q>GQɡGl5rjRDܴVKLt3ԥڅ·b6e|6,5 1lZE5+tt!̄:RK@iDҁsN'_AX")il{;
l.eH`[c珊
;
a1=1/2,Sn=n^2an-n(n-1),求Sn和an
数列{an},中,a1=1/3,设Sn为数列{an}的前n项和,Sn=n(2n-1)an 求Sn
数列an满足a1=1/3,Sn=n(2n-1)an,求an
a1=1,Sn=n^2an,求an
Sn=n(2n-1)an a1=1/3求数列的Sn,an
已知a1=3,an=Sn-1+2^n(n大于等于2),求an,Sn?
已知a1=3,an=Sn-1+2^n(n大于等于2),求an,Sn?
Sn=n(2n-1)an,a1=1/3,求an
a1=3,an=Sn-1+2n次方.n大于或等于2.求an和Sn
a1=3,an=Sn-1+2的n次方.n大于或等于2.求an和Sn
a1=1,an+1=an+3^n-n,求an与sn
数列{an}前n项和为sn,若sn/n=3s(n-1)/n-1(n≥2),a1=3,求an
设数列{an}中,a1=1且(2n+1)an=(2n-3)a(n-1),(n大于等于2),求{an},sn
已知数列{an},其中a1=1,a(n+1)=3^(2n-1)*an(n∈N),数列{bn}的前n项和Sn=log3(an/9^n)(n∈N)求an bn
已知Sn为等差数列{an}的前n项和,Sn=12n-n².(1)|a1|+|a2|+|a3|+...+|a10|;(2)求|a1|+|a2|+...+|an|
已知数列an中 a1=-2且an+1=sn(n+1为下标),求an,sn
已知数列{an}满足:a1=3,an=Sn-1+2n,求数列an及sn
已知数列{an}的前n项和为Sn,若a1=1/2,Sn=n^2an-n(n-1)求Sn,an