x2+y2=19.36 x:y=:16:10 求x和y各自的值
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已知:x2-y2=16,x+y=2,求:3x-3y/y2-x2+x2-2xy+y2/x2-y2-x2-x-6/x+2除以(x+y)
x2+y2=19.36 x:y=:16:10 求x和y各自的值
x2+y2=208(x-y)
我做对了吗.x2(x-y)+y2(y-x)= x2(x-y)-y2(x-y)=x2-y2=(x+y)(x-y)
x2-2xy+y2=4 x2+y2-x-y=6 解不等式x2-2xy+y2=4 x2+y2-x-y=6 解不等式
已知x,y满足(x2+y2)(x2+y2-1)=2,则x2+y2的值为多少?x2,y2表示x和y的平方
x2+y2+x+y=18 x2+y2-2x-4x=24 解方程组
X2y2-x2-y2+1 =x2(y2-1)-(y2-1) =(y2-1)(x2-1) =(y+1)(y-1)(x+1)(x-1) 中的=x2(y2-1)-(y2-1) =(y2-1)(x2-1是怎么算出来的?
y=x+√(1-x2) y2=x2+(1-x2)+2x√(1-x2)
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