sin(-19π/6)= sin(-16π/3)= cos(-79π/6)=
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sin(-19π/6)=?已知[3Sin(π+a)+Cos(π-a)]/4Sin(-a)-Sin(5π/2+a)=2,求tan a
sin(-19π/6)=;sin(-16π/3)=;cos(-79π/6)=;tan(-26π/3)=;sin(15π/4)=;cos(-60°)-sin(-210°)=?
sin(-19π/6)= sin(-16π/3)= cos(-79π/6)=
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