sin(x+11π/6)=sin(x-π/6)怎么得到的
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/17 12:32:54
![sin(x+11π/6)=sin(x-π/6)怎么得到的](/uploads/image/z/2765558-38-8.jpg?t=sin%EF%BC%88x%2B11%CF%80%2F6%EF%BC%89%3Dsin%EF%BC%88x-%CF%80%2F6%EF%BC%89%E6%80%8E%E4%B9%88%E5%BE%97%E5%88%B0%E7%9A%84)
xjP_e+zo&7_=$M8%bSnM:٩0.GK[_4]ER=?{\>f&>Q[2YLN|K&[UmZh?mI(XL_
?czHA|sQGVϴOzm*p^Xip9JyD!"^;oOY\pn,(7Y_U]W,έ<ϹUljx
6_;ecX-M B[uE!aYGoʚ!lP3C e srːD$ Ѕxs(+T` !M (JS*sY@mJ%hBϒm"ϪtF)sa䕷kGt=yG?&B>"d4S&36R}/5{zw&aWx X)
sin(x+11π/6)=sin(x-π/6)怎么得到的
sin(x+11π/6)=sin(x-π/6)怎么得到的
sin(x+11π/6)=sin(x-π/6)怎么得到的
sin(x+11π/6)=sin(x+2π-π/6),因为2π是一个周期,可以消去,于是得到答案sin(x-π/6)
诱导公式的应用sin(x+2kπ)=sinx,
sin(x+11π/6-2π)=sin(x-π/6)
sin函数曲线,每2π一个周期, 所以sin(x)=sin(x+2π) 同理sin(x-π/6)=sin(x-π/6+2π)=sin(x+11π/6)
根据正弦图像及规律,周期为2π,然后有sint=sin(t+2π),所以sin(x-π/6)=sin(x-π/6+2π),即为sin(x-π/6)=sin(x+11/6π)
sin(x+11π/6)=sin(x-π/6)怎么得到的
已知sin(x+π/6)=1/4,求sin(5π/6-x)+sin^2(11π/6-x)如题,
已知函数f(x)=[2sin(x-π/6)+√3sin x]cos x+sin^2x,x∈R
y=sin(x+π /6)sin(x-π/6)的最小周期是
sin^2(π/3-x)+sin^2(π/6+x)
2sin(x+π/4)sin(x-π/4)=?
sinπ(x-1)=-sinπx如何证明
已知函数f(x)=sin(2x+π/6)+sin(2x+π/6)+2cos²x
f(x)=sin(2x+π/6)+2sin(x-π/4)sin(x+π/4) 怎么化简为形函数
已知sin(x+π/6)=1/3,求sin(5π/6-x)+sin^2(π/3-x)
已知sin(x+π/6)=1/4,求sin(5π/6-x)+sin^2(π/3-x)
若tanx=2,则2sin平方x-3sin(π-x)sin(π/2-x)=
2*sin(x+π/6)求导.
sin(x+π/4)
f(x)=sin(x+π/6)+sin(x-π/6)+cosx 的单调递增区间
已知sinα(x+π/6)=1/4,则sin(5π/6-x)+sin(π/3-x)的平方=?
已知sin(X+π/6)=2/3,求sin(X+19π/6)+sin²(π/3-X)的值?
已知sin(X+π/6)=2/3,求sin(X+19π/6)+sin²(π/3-X)的值?