f(z)=2z+z'-3i f(z'+i)=6-3i,则f(-z)=?z',z是复数!
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/07 03:57:05
x)KӨz֨JJ]8SWԴ5rtvLЭҴRשz6c%ϦnPI*'V'X-v;J~:{<d⧭K|gH*@*bT4 '=ٽJݶB2SBuNЁXdG=k&WhkWjfB|F:F:@Ìt5,M@K5A~Ib(.B6SF 1
f(z)=2z+z'-3i f(z'+i)=6-3i,则f(-z)=?z',z是复数!
(2)f(z)=z^2/(z^2+1)(z^2+9),求Resf(z)(z=i)和Resf(z)(z=3i)
f(z)=z^2/(z^2+1)(z^2+9),求Resf(z)(z=i)和Resf(z)(z=3i)
f(z)=z^2/{(z^2+1)*(z^2+9)}求Res(z=i)f(z)和Res(z=3i)f(z)
f(z)=2z+z的共轭-3i,f(z的共轭+i)=6-3i,试求f(-z)
已知f(z)=|1+z|-z(拔),又f(-z)=10+3i,求复数z已知f(z)=|1+z|-z(拔),又f(-z)=10+3i,求复数z
f(z)=2z+(共轭z)-3i,f(z0共轭+i)=6-3i,求f(-z0)注:共轭z表示z的共轭复数
已知f(z)=z^4+4z^3+8z^2+8z+5,则f(-1+2i)等于多少
已知f(z+i)=z+2z-2i,则f(i)=?
已知f(z)=1+IzI-z,且f(-z)=10+3i,求复数z
若z的共轭复数为z f(z+i)=z+2i则 f(3+2i)=
F(z)=|1+z|-z的共扼复数,且F(-z)=10-3i,求复数z
复变函数f(z)=z^2/{(z^2+1)*(z^2+9)}求Res(z=i)f(z)和Res(z=3i)f(z)
复变函数f(z)=z^2/{(z^2+1)*(z^2+9)}求Res(z=i)f(z)和Res(z=3i)f(z)
已知f(z)=2z+z^2+(1+i),则f(i)的值是
已知f(z)=2z+z²+(1+i)则f(i)的值是
已知f(z+i)=3z-2i,则f(i)=
f(z)=2z+z'-3i f(z'+i)=6-3i,则f(-z)=?我知道答案是-6-4i,大概过程我也明白,但没算明白,