圆:x^2+y^2-2x-2y+1=0上的点到直线x-y=2的距离最大值是a:2b:1+√2c:1+2/√2d:1+2√2

x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2 M(x,y)在圆x^2+y^2=1上移动,求点Q(x(x+y),y(x+y))的轨迹 点p(x,y)在圆x²+y²-2x-2y+1=0上则x+1/y的最小值 已知点(x,y)是圆x平方+y平方-4x+1=0上一动点 i)求y/x的最大值 2)求y-x的最...已知点(x,y)是圆x平方+y平方-4x+1=0上一动点 i)求y/x的最大值 2)求y-x的最小值 设x大于1,y大于0,x^y+x^-y=2根号二,x^y-x^-y等于? 已知点P(x,y)在圆x^2+y^2-2y=0上运动,则y-1/x-2的最大值与最小值分别为? 设点p(x,y)在圆x^2+(y-1)^2=1上.y+2/x+1的最小值 已知实数x,y满足x-y大于等于0,x+y-1小于等于0已知实数x,y满足x-y大于等于0,x+y-1小于等于0,y+1大于等于0,若点P(x,y)在圆x^2+(y-1)^2=a(a大于0)的内部或圆上,则a最小值为 2y(x+二分之一y)-[(x+y)(x-y)+2y(y+x)],其中|x-1|=2 （x-y)(x+y)-(x+y)^2+2y(y-x),其中x=1,y=3. mathematica软件,已知y[x],Y=f1(x),X(x)=f2(x),如何plot Y[X]?y[x_] := x + 9.81/2*x*xk=1X[x] = x - k*y'[x]/(1 + (y'[x])^2)^0.5Y[x] = y[x] + k/(1 + (y'[x])^2)^0.5Plot[{y[x],Y[X],},{x,0,2}] 已知x+y=a,2x-y=-2a,求[（x/y-y/x)/(x+y)-x(1/x-1/y)]/[(x+1)/y]的值 若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值 [(-x-y)(-x+y)-(x+y)^2-x(y-y^2)}÷1/2y 已知x,y满足约束条件：x-y+1>=0,x+y-2>=0,x 点(x,y)在圆x^2+y^2-6x-6y+12=0上,求x^2+y^2的最值 点p(x,y)在圆x^2+y^2-6x-6y+12=0上,求x^2+y^2最值如题 动点P(x,y)在圆上x^2+(y-1)^2=1,求(y-1)/(x-2)的最大值和2x+y的最小值