设数列的{an}前n项和为Sn 且满足2a(n)= 3Sn-5/2S(n-1)-2(n>=2) a(1)=2.(1) 求数列{an}的通项公式(2)证明:1/2(log(2)Sn+log(2)S(n+2))<log(2)S(n+1)
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