sin(2x+∏/6)-cos(2x+∏/3)最小正周期和最大值是多少?
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/11 14:38:58
x)+0~ѯo_k>tCN\lz@"K?mlKf=0&HrClh-NF1,ʴ!<F@1
~(DQ,c8FXH~qAb6`Y/|c}/w~I X!
化简(sin^2x-cos^4x+cos^2x-sin^4x)/(sin^2x-cos^6x+cos^2x-sin^6x)
2(sin^6x+cos^6)-3(sin^4x+cos^4x)
已知tan=2,求(cos x+sin x)/(cos x-sin x)+sin^2x
化简(sin x+cos x-1)(sin x-cos x+1)/sin 2x
sin(2x+∏/6)-cos(2x+∏/3)最小正周期和最大值是多少?
化简√2sin(∏/4-X)+√6cos(∏/4-x)
证明一个sin&cos的等式证明 1+sin^2(x)+sin^4(x)+sin^6(x)=[1-sin^8(x)]/[cos^2(x)]
2cos x (sin x -cos x)+1
y=2cos x (sin x+cos x)
化简sin(x)cos(x)cos(2x)
化简sin(x)cos(x)cos(2x)
sin x cos x cos 2x 化简
化简(1)√3sin x+cos x (2)√2(sin x-cos x) (3)√2cos x-√6sin x
(sin^2x+cos^2x )(sin^2x-cos^2x)怎么得sin^2x-cos^2x?
已知sin(x)+3cos(x)=2,求sin(x)-cos(x)/sin(x)+cos(x)=?
化简 cos^2(x)*sin^2(x)-sin^2(x)
化简 cos^(2)(x)*sin^(2)(x)-sin^(2)(x)
化简sin^4x-sin^2x+cos^2x