几何如图AB=AE,AD=AC,角BCA=81度,则角BDF=_______证明方法!我知道等于81度!

几何如图AB=AE,AD=AC,角BCA=81度,则角BDF=_______证明方法!我知道等于81度! 一到数学几何如图,在梯形ABCD中,AD‖BC,AB=AD+BC,E为CD的中点,连接AE、BE说明：BE平分∠ABC,AE平分∠BAD 如图,DE//BC,请问AD:AC=AE:AB?AD:AE=AB:AC? 如图,CD垂直AD,AB垂直AD,角BCA=角BAC,AE垂直BC,垂足为E,求证CD=CE 如图,AD⊥AE,AB垂直AC,AD=AE,AB=AC,AD⊥AE ,AB=AC,求证：三角形ABD≌三角形ACE 【圆】初三几何如图,已知AC切⊙o于A,CB顺次交⊙于D,B两点,AC=6,BD=5,连接AD,AB.则线段DC长为____. 如图,AB=AD,AC=AE, 如图,已知AD/DB=AE/EC,求证 :AD/AB=AE/AC. 如图,AB⊥AC,AD⊥AE,AB=AC,AD=AE.求证BE⊥CD 如图,AB⊥AC,AD⊥AE,AB=AC,AD=AE.求证BE⊥CD 如图AB⊥AC,AD⊥AE,AB=AC,AD=AE.求证:△DAC≌三角形EAB 如图,已知：AB=AE,AC=AD,AC⊥AD,AB⊥AE.求证：ED⊥BC. AD是三角形ABC的中线,点E在BC的延长线上,CE=AB,角BAC=角BCA,求：AE=2AD 如图,CD⊥AD,AB⊥AD,∠BCA=∠BAC,且AE⊥BC,垂足为E,试证明CD=CE急 如图,CD⊥AD,AB⊥AD,∠BCA=∠BAC,又AE⊥BC,垂足为E.试说明：CD=CE. 如图,AB=AC,∠BCA=90°,AE⊥BE,且BE=2AE,求证BE平分∠ABC.图为什么传不上来..... 已知:如图,AC/AD=AB/DE=BC/AE.求证AB=AE 已知,如图,AD/AC=DE/AB=AE/BC,求证AB=AE