设f(x)=(1+x)^6(1-x)^5,则函数f'(x)中x^3的系数是是多少?

设f(x)=1/x(x 设f(x)=1-x,(x 设函数f(x)满足f(x-1)=2x-5,求f(x平方) 设f(x)满足f(1/x)=x/1-x设设f(x)满足f(1/x)=x/1-x ,则f(x+1)=? 设f(x)=(x平方-1)/(x-1) (x 设f(x)=(x平方-1)/(x-1) (x 设f(x)=x/2+1/x(x 设f(x)=lgx,证明f(x)+f(x+1)=f[x(x+1)] 设函数f(x)满足f(x)+2f(1/x)=x,求f(x) 设f(x)={1+x (-1 设f(x)={1+x (-1 设f(x)= 1-x分之x 求f[(fx)]和f{f[f(x)]} 设f(x)=x平方+6x+3,则f(x+1)=? 设函数f(x-1)=2x²+3x-5,则f(x)=? 设f(x)=(2x+5)^2*(3x-1)^4,求f'(x) 设f(x){e^(1/x),x 设2f(x)+xf(1/x)=(x+2x)/(x+1),求f(x). 设函数f(x)=(x-1)(x-2)...(x-100)(x>100),求F'(X)